Quick C question
nmeyers at javalinux.net
nmeyers at javalinux.net
Wed Nov 16 10:46:50 EST 2005
On Wed, Nov 16, 2005 at 10:35:42AM -0500, Anthony Gabrielson wrote:
> Hello,
> I'm trying to some image processing in C and I won't know ahead of
> time what the dimensions of the image are. So I would like to do a
> multi-dim array with a pointer so I can malloc the space and hopefully be
> good. The problem is that the compiler doesn't seem to agree with this
> strategy. So does anyone have an idea of how to do something like the
> attached example with pointers by chance?
Arrays are one-dimensional beasts - unless you know something that can
give the compiler a hint (like the size of all but the last dimension)
at compile-time, you're going to need to manage this is an array of
array pointers.
int n, **array;
array = (int **)malloc(sizeof(int *) * D1);
for (n = 0; n < D1; n++) {
array[n] = (int *)malloc(sizeof(int) * D2);
}
. . .
. . .
. . .
for (n = 0; n < D1; n++) {
free(array[n]);
}
free(array);
Nathan
>
> #include <stdio.h>
>
> #define D1 4
> #define D2 2
>
> int main(){
>
> int *array;
>
> array = malloc(sizeof(int) * (D1 * D2));
>
> array[1][1] = 32;
>
> printf("Elem[1][1] = %d\n",array[1][1]);
>
> free(array);
>
> return 0;
> }
>
> Thanks,
> Anthony
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